The original question was: Some elementary particles spontaneously break apart at a given rate. Can the same be said about normally stable atoms and molecules? That is, even though they are stable, does their natural internal activity lead to a certain probability that they will come apart?
Physicist: Nope! A thing is either stable or it’s unstable. For example, carbon 12 is stable forever.
However, some of the things that we consider to be stable are only very nearly stable. For example, Uranium 238 has a half-life of about 4.6 billion years, which is basically forever.
The question comes down to “if this thing falls apart does it release energy?” If it does release energy then it’s unstable, and if it doesn’t then it’s stable (or you’d have to add energy to knock it apart).
Answer gravy: In an atomic nucleus there are two forces acting against each other: the Nuclear Strong force and the Electric force. The Strong force acts on protons and neutrons and holds them together, while the Electric force acts on protons and tries to make them fly apart (“likes repel”). Over distance the Electric force gets weaker, but it still has an infinite range. The Strong force on the other hand has an extremely limited range.
So the Electric force is working to push the nucleus apart, and it can work with every proton in the nucleus (size of an atom < ∞). But the Strong force only works between the protons and neutrons that are basically touching. A large atom is way too big for the Strong force to work across. So while the force that keeps each proton or neutron in the nucleus levels out for bigger and bigger atoms, the force pushing the nucleus apart just keeps going up.
A good way to talk about forces and energies is to draw a “potential diagram”.
The combination of the strong pull and the electric push creates a bump that, normally, would be impassible. However, (basically) because of the uncertainty principle, parts of the nucleus can “tunnel” out through that potential wall. If they can gain energy by sliding away then they can stay outside, and fly off as radiation and decay products. If they find that they need energy they don’t have, then they stay where they are (in the nucleus), since energy conservation makes the “away from the atom” state impossible.
So whether or not something is stable depends on whether or not there’s a net energy gain by undergoing radioactive decay. The stability of a particular isotope has to do with the shape and height of that “potential bump”, which varies wildly from isotope to isotope. But in general, the heavier something is, the shorter its half-life (it’s easier for stuff to tunnel out).
Wait… I’m confused… How can an atom “borrow” energy and then pay it back by decaying? How could it borrow energy in the first place? Or is this just the weird world of quantum mechanics again?
@Bob
radioactive decay doesn’t need to borrow energy; the atom has too much energy to start with* and in the right circumstances the energy is carried away by one of the neutrons / protons (whether they decay or not). some atoms are naturally unstable this way, since due to their atomic structure (due to number of particles), they always will have excess energy for some isotopes. other atoms just need a tiny kick to make them unstable, but otherwise they will not decay on their own.
most of the time you just need to abide by principle of least action – physics tends to minimize the energy you’re working with, resulting with the easiest (least-energetic) options to be ‘attempted’ first. under this analogy if none of your attempts ‘do’ anything it is possible a higher energy state is required. eg, atomic stability…
* = too much energy also depends on the configuration / arrangement of the atom itself.
What about the still unresolved lifetime of the proton?
If it’s finite isn’t everything else?
Not to mention the big rip, but I guess that’s a different critter.
– greg
hi i’m a morrocan student and i’m interested of physics learning and i need some advice to be a super physicien learner so please i need some help and thank you 🙂
@aya
Learn all the math you possibly can and find professional physicists to talk with.
Like anything, spend time doing it and make sure there’s someone around to let you know when you’re doing it wrong.